A) \[{{A}_{1}}={{A}_{2}}\]
B) \[\frac{{{A}_{1}}}{{{A}_{2}}}=\frac{{{K}_{1}}}{{{K}_{2}}}\]
C) \[\frac{{{A}_{1}}}{{{A}_{2}}}=\frac{{{K}_{2}}}{{{K}_{1}}}\]
D) \[{{K}_{1}}={{K}_{2}}\]
Correct Answer: C
Solution :
[c] \[\frac{\Delta {{Q}_{1}}}{\Delta t}=\frac{\Delta {{Q}_{2}}}{\Delta t}\] \[\Rightarrow {{K}_{1}}{{A}_{1}}\frac{{{T}_{1}}-{{T}_{2}}}{{{L}_{1}}}={{K}_{2}}{{A}_{2}}\frac{{{T}_{1}}-{{T}_{2}}}{{{L}_{2}}}\] \[\left( {{L}_{1}}={{L}_{2}} \right)\therefore \frac{{{A}_{1}}}{{{A}_{2}}}=\frac{{{K}_{2}}}{{{K}_{1}}}\]You need to login to perform this action.
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