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JEE Main & Advanced Physics Thermodynamical Processes Question Bank Self Evaluation Test - Thermodynamics

  • question_answer
    A perfect gas goes from a state A to another state B by absorbing \[8\times {{10}^{5}}J\] of heat and doing \[6.5\times {{10}^{5}}J\] of external work. It is now transferred between the same two states in another process in which it absorbs \[{{10}^{5}}J\] of heat. hi the second process

    A) work done by gas is \[{{10}^{5}}J\]  

    B) work done on gas is \[{{10}^{5}}J\]

    C) work done by gas is \[0.5\times {{10}^{5}}J\]

    D) work done on the gas is \[0.5\times {{10}^{5}}\text{ }J\]

    Correct Answer: D

    Solution :

    [d] \[dU=dQ-dW=\left( 8\times 105-6.5\times 105 \right)\] \[=1.5\times {{10}^{5}}J\] \[dW=dQ-dU={{10}^{5}}-1.5\times {{10}^{5}}\] \[=-0.5\times {{10}^{5}}\] \[-\]ve sign indicates that work done on the gas is  \[0.5\times {{10}^{5}}J\]


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