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JEE Main & Advanced Physics Thermodynamical Processes Question Bank Self Evaluation Test - Thermodynamics

  • question_answer
    A closed system undergoes a process \[1\to 2\] for which the values \[{{W}_{1-2}}\] and \[{{Q}_{1-2}}\] are 50 kJ and - 20 kJ respectively. If the system is returned to state 1 and \[{{Q}_{1\to 2}}+10kJ\] the work done \[{{W}_{1\to 2}}\]is

    A) 40 kJ

    B) 50 kJ 

    C) -60 kJ

    D) -50 kJ

    Correct Answer: C

    Solution :

    [c] \[-20=\Delta U+50\Rightarrow \Delta U=-70.\] \[\text{From }2\to 1,\Delta U=70kJ.\] \[\text{Now }10=70+W\Rightarrow W=-60kJ.\]


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