A) \[-2730\text{ }kJ\]
B) \[-462\,kJ\]
C) \[-1365\,kJ\]
D) \[+2730\,kJ\]
Correct Answer: B
Solution :
[b] \[2Al+\frac{3}{2}{{O}_{2}}\to A{{l}_{2}}{{O}_{3}},\text{ }\Delta H=-1596kJ\].....(i) \[2Cr+\frac{3}{2}{{O}_{2}}\to C{{r}_{2}}{{O}_{3}},\,\Delta H=-~1134kJ\] .......(ii) By (i)-(ii) \[2Al+C{{r}_{2}}{{O}_{3}}\to 2Cr+A{{l}_{2}}{{O}_{3}},\text{ }\Delta H=-462\text{ }kJ.\]You need to login to perform this action.
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