A) 15 : 3
B) 42 : 1
C) 1 : 42
D) 1 : 84
Correct Answer: D
Solution :
[d] No. of moles of \[{{O}_{2}}\] required to supplied 30 kJ heat to second reaction \[=\frac{30}{1260}\times \frac{3}{2}=\frac{1}{28}\] \[{{n}_{{{O}_{2}}}}:{{n}_{{{H}_{2}}}}=\frac{1}{28}:\,or\,\,1:84\]You need to login to perform this action.
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