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JEE Main & Advanced Physics Thermodynamical Processes Question Bank Self Evaluation Test - Thermodynamics

  • question_answer
    Certain perfect gas is found to obey \[P{{V}^{3/2}}=\] constant during an adiabatic process. If such a gas at initial temperature T is adiabatically compressed to half the initial volume, its final temperature will be

    A) \[\sqrt{2}T\]      

    B)        \[~2T~~~\]

    C) \[2\sqrt{2}T\]    

    D)        \[4T\]

    Correct Answer: A

    Solution :

    [a] \[P{{V}^{3/2}}=\text{constant}\] \[PV=nRT\] \[\Rightarrow {{V}^{1/2}}T=\text{const}\text{.}\] \[\Rightarrow {{\left( \frac{V}{2} \right)}^{1/2}}T'=\text{const}\text{.}\] \[\Rightarrow T'=T\sqrt{2}\]


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