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JEE Main & Advanced Physics Thermodynamical Processes Question Bank Self Evaluation Test - Thermodynamics

  • question_answer
    A 500 ml sealed cylinder contains nitrogen at a pressure of 1 atm. A tiny glass tube lies at the bottom of the cylinder. Its volume is 0.50 ml and it contains hydrogen at a pressure of 4.5 atm. The glass tube is broken so that hydrogen also fills the cylinder. The new pressure in the cylinder is \[(1\text{ }atm=1\times 105N/{{m}^{2}})\]

    A) 76.34 cm Hg

    B) 82.40 cm Hg

    C) 94.24 cm Hg

    D) 104.34 cm Hg

    Correct Answer: A

    Solution :

    [a] For tiny glass tube, \[{{P}_{1}}{{V}_{1}}={{P}_{2}}{{V}_{2}}\] \[\therefore {{P}_{2}}=\frac{{{P}_{1}}{{V}_{1}}}{{{V}_{2}}}=\frac{4.5\times 0.50}{500}=0.0045\,\,atm.\] Thus \[P=\text{1}\,atm+0.0045\,atm\] \[=1.0045atm=76.34\text{ cm of }Hg.\]


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