A) \[13.0\text{ }kcal/mol\]
B) \[-13.0\text{ }kcal/mol\]
C) \[27.0\text{ }kcal\]
D) \[-7.0\text{ }kcal/mol\]
Correct Answer: C
Solution :
\[3{{H}_{2}}O(l)\to 3{{H}_{2}}O(g);\] \[\Delta n=3,\Delta E=\Delta H-\Delta nRT\] \[=30-3\times \frac{2}{1000}\times 500=27kcal\]You need to login to perform this action.
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