A) \[41.00kJ\,mo{{l}^{-1}}\]
B) \[4.100kJ\,mo{{l}^{-1}}\]
C) \[3.7904\text{ }kJ\text{ }mo{{l}^{-1}}\]
D) \[37.904\text{ }kJ\text{ }mo{{l}^{-1}}\]
Correct Answer: D
Solution :
[d] Given \[\Delta H=41\text{ }kJ\text{ }mo{{l}^{-1}}=41000J\text{ }mo{{l}^{-1}}\] \[T=100{}^\circ C=273+100=373\text{ }K\] \[\Delta n=1\] \[\Delta U=\Delta H-\Delta nRT=41000-\left( 1\times 8.314\times 373 \right)\] \[=37898.88\,Jmo{{l}^{-1}}\simeq 37.9kJ\,mo{{l}^{-1}}\]You need to login to perform this action.
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