A) \[-100kcal\]
B) \[-200\text{ }kcal\]
C) \[+100\text{ }kcal\]
D) \[+200\text{ }kcal\]
Correct Answer: A
Solution :
[a] I-II. gives, \[2Al+F{{e}_{2}}{{O}_{3}}\to 2Fe+A{{l}_{2}}{{O}_{3}}\] we have \[-400-\left( -200 \right)=-200\]; For one mole of iron the value is \[-100\] calYou need to login to perform this action.
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