A) \[40.3\text{ }kJ/mol\]
B) \[43.2\text{ }kJ/mol\]
C) \[4.03\text{ }kJ/mol\]
D) None of these
Correct Answer: A
Solution :
[a] 1 watt = 1 J/sec Total heat supplied for \[36mL\,{{H}_{2}}O\] \[=806\times 100\] \[=80600\text{ }J\] \[\Delta {{H}_{vap}}=\frac{80600}{36}\times 18\] \[=40300\text{ }J\text{ }or\text{ }40.3\text{ }kJ/mol\]You need to login to perform this action.
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