A) 25
B) 20
C) 15
D) 10
Correct Answer: B
Solution :
[b] The enthalpy of ionisation of weak acid is given by \[\Delta {{H}_{ion}}(HA)\] \[=\Delta {{H}_{N}}\] (weak acid / strong base) - \[\Delta {{H}_{N}}\](strong acid / strong base) \[=-56.1-\left( -57.3 \right)=1.2\text{ }kJ\,mo{{l}^{-1}}\] \[\Delta {{H}_{(ionisation)}}=1.5\,kJmo{{l}^{\text{-}1}}\] Hence % ionisation in 1 M solution \[=\frac{(1.5-1.2)}{1.5}\times 100=20%\]%You need to login to perform this action.
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