A) 372 K and 330 K
B) 330 K and 268 K
C) 310 K and 248 K
D) 372 K and 310 K
Correct Answer: D
Solution :
[d] \[{{\eta }_{1}}=1-\frac{{{T}_{2}}}{{{T}_{1}}}\Rightarrow \frac{1}{6}=1-\frac{{{T}_{2}}}{{{T}_{1}}}\Rightarrow \frac{{{T}_{2}}}{{{T}_{1}}}=\frac{5}{6}\] ...(i) \[{{\eta }_{2}}=1-\frac{{{T}_{2}}-62}{{{T}_{1}}}\Rightarrow \frac{1}{3}=1-\frac{{{T}_{2}}-62}{{{T}_{1}}}\] ?(ii) On solving Eqs. (i) and (ii) \[{{T}_{1}}=372K\] and \[{{T}_{2}}=310K\]You need to login to perform this action.
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