A) \[\frac{1}{4}\]
B) \[\frac{1}{2}\]
C) \[\frac{2}{3}\]
D) \[\frac{1}{3}\]
Correct Answer: D
Solution :
[d] \[{{Q}_{1}}={{T}_{0}}{{S}_{0}}+\frac{1}{2}{{T}_{0}}{{S}_{0}}=\frac{3}{2}{{T}_{0}}{{S}_{0}}\] \[{{Q}_{2}}={{T}_{0}}(2{{S}_{0}}-{{S}_{0}})={{T}_{0}}{{S}_{0}}\] and \[{{Q}_{3}}=0\] \[\eta =\frac{W}{{{Q}_{1}}}=\frac{{{Q}_{1}}-{{Q}_{2}}}{{{Q}_{1}}}\] \[=1-\frac{{{Q}_{1}}}{{{Q}_{2}}}=1-\frac{{{T}_{0}}{{S}_{0}}}{\frac{3}{2}{{T}_{0}}{{S}_{0}}}=\frac{1}{3}\]You need to login to perform this action.
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