A) \[{{K}_{P}}=-RT\] In \[\Delta {{G}^{{}^\circ }}\]
B) \[{{K}_{P}}={{\left[ \frac{e}{RT} \right]}^{\Delta {{G}^{{}^\circ }}}}\]
C) \[{{K}_{P}}=-\frac{\Delta G}{RT}\]
D) \[{{K}_{P}}={{e}^{-\Delta {{G}^{{}^\circ }}/RT}}\]
Correct Answer: D
Solution :
[d] \[\Delta G=-RT\]ln \[{{K}_{P}}\] or \[{{K}_{P}}={{e}^{-\Delta G/RT}}\]You need to login to perform this action.
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