A) zero
B) 80 J
C) 20 J
D) -20 J
Correct Answer: C
Solution :
[c] Given that \[dQ=-30\text{ }J\]and\[~dW=-10J\] \[{{E}_{i}}=40\text{ }J\] and let final internal energy\[={{E}_{f}}\] So, \[dQ={{E}_{f}}-{{E}_{i}}+dW\] \[-30=\text{ }{{E}_{f}}-40-10\] \[{{E}_{f}}=20J\]You need to login to perform this action.
You will be redirected in
3 sec