A) 320 kJ
B) 282 kJ
C) 141 kJ
D) 423 kJ
Correct Answer: B
Solution :
[b] \[Q=mC\Delta r=1.5\times 0.12\times 4200\times \left( 400-25 \right)\] \[=2.83\times {{10}^{5}}J\] \[W=P\left( \Delta V \right)=P(V\Delta T)\] \[=105\times \left( 5\times 10-2 \right)3\times 3.5\times 10-5\times 375=0.164\text{ }J\]\[\text{Thus }Q=\Delta U+W\] \[or\text{ }2.83\times {{10}^{5}}=\Delta U+0.164;\Delta U=282kJ\]You need to login to perform this action.
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