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JEE Main & Advanced Physics Thermodynamical Processes Question Bank Self Evaluation Test - Thermodynamics

  • question_answer
    Suppose 0.5 mole of an ideal gas undergoes an isothermal expansion as energy is added to its heat Q.            Graph shows the final volume \[{{V}_{f}}\] versus Q.   The temperature of the gas is (use ln 9 = 2 and\[R=\frac{25}{3}J/mol-K\])

    A) 360 K

    B) 293 K

    C) 386 K

    D) 412 K

    Correct Answer: A

    Solution :

    [a] \[Q=W=nRT\text{ in }\frac{{{V}_{f}}}{{{V}_{i}}}\] \[T=\frac{Q}{nR\text{ In}\left( {{V}_{f}}/{{V}_{i}} \right)}=\frac{1500}{0.5\times 25/3\times \text{ ln 3}}\] \[\Rightarrow T=\frac{1500}{0.5\times 25/3\times \text{1}}=360K\]


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