A) \[2.66\times {{10}^{8}}\]
B) \[5.81\times {{10}^{8}}\]
C) \[1.18\times {{10}^{7}}\]
D) \[1.98\times {{10}^{8}}\]
Correct Answer: A
Solution :
[a] \[\Delta G=-RT\] ln \[{{K}_{eq}}\]: Normal body temperature \[=37{}^\circ C\] \[\Rightarrow -50\frac{KJ}{mol}=8.314\frac{J}{Kmol}\times 310\,\ln {{K}_{eq}}\] \[\Rightarrow 19.39=\ln {{K}_{eq}}\] \[\Rightarrow {{K}_{eq}}=2.6\times {{10}^{8}}\]You need to login to perform this action.
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