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JEE Main & Advanced Physics Thermodynamical Processes Question Bank Self Evaluation Test - Thermodynamics

  • question_answer
    In a Carnot engine, the temperature of reservoir is \[927{}^\circ C\] and that of sink is\[27{}^\circ C\].  If the work done by the engine when it transfers heat from reservoir to sink is \[12.6\times {{10}^{6}}J,\] the quantity of heat absorbed by the engine from the reservoir is

    A) \[16.8\times {{10}^{6}}J\]

    B) \[4\times {{10}^{6}}J\]

    C) \[7.6\times {{10}^{6}}J\]

    D) \[4.2\times {{10}^{6}}J\]

    Correct Answer: A

    Solution :

    [a] As we know \[\eta =\frac{W}{{{Q}_{1}}}=1-\frac{{{T}_{2}}}{{{T}_{1}}}\] \[\Rightarrow \eta =1-\frac{300K}{1200K}=\frac{3}{4}\] \[\frac{3}{4}=\frac{W}{{{Q}_{1}}}\Rightarrow {{Q}_{1}}=W\times \frac{4}{3}\Rightarrow {{Q}_{1}}=12.6\times {{10}^{6}}\times \frac{4}{3}\] \[{{Q}_{1}}=16.8\times {{10}^{6}}J.\]


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