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JEE Main & Advanced Physics Thermodynamical Processes Question Bank Self Evaluation Test - Thermodynamics

  • question_answer
    110 joules of heat is added to a gaseous system, whose internal energy is 40J; then the amount of external work done is

    A) 150 J

    B) 70 J   

    C) 110 J

    D) 40 J

    Correct Answer: B

    Solution :

    [b] \[\Delta Q=\Delta U+\Delta W\] \[\Rightarrow \Delta W=\Delta Q-\Delta U=110-40=70J\]


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