A) 12
B) \[\frac{12}{5}\]
C) \[\frac{\sqrt{12}}{5}\]
D) \[\sqrt{12}\]
Correct Answer: B
Solution :
[b] For the orthogonal section \[{{C}_{1}}P\] and \[{{C}_{2}}P\] are pendicular where \[{{C}_{1}}\]and \[{{C}_{2}}\] are centers of sphere of radii 4 and 3 respectively Now \[{{C}_{1}}P=4\] and\[{{C}_{2}}P=3\], so \[\tan \theta =\frac{3}{4}\] \[\therefore \] Radius of circle of intersection \[OP={{C}_{1}}P\sin \theta =4\times \frac{3}{5}=\frac{12}{5}\]You need to login to perform this action.
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