A) (2, 3, 4)
B) (14, 0, 7)
C) (-2, 0, -1)
D) (2, 0, -1)
Correct Answer: D
Solution :
[d] Any plane through (1, -2, -3) is \[A(x-1)+B(y+2)+C(z-3)=0\] (1) The point \[(-1,2,-1)\] lies in this plane if \[-2A+4B-4C=0\] i.e., if \[A-2B+2C=0\] (2) The plane (1) is parallel to the given line with d. r., 2, 3, 4 if \[2A+3B+4C=0\] (3) From (2) and (3), we have \[\frac{A}{-8-6}=\frac{B}{4-4}=\frac{C}{3+4}\] \[\Rightarrow \frac{A}{-14}=\frac{B}{0}=\frac{C}{7}\Rightarrow A:B:C=2:0:-1\]You need to login to perform this action.
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