A) -1
B) 1
C) -2
D) 2
Correct Answer: C
Solution :
[c] Plane \[2ax-3ay+4az+6=0\] passes through the midpoint of the centre of spheres \[{{x}^{2}}+{{y}^{2}}+{{z}^{2}}+6x-8y-2z=13\] and \[{{x}^{2}}+{{y}^{2}}+{{z}^{2}}-10x+4y-2z=8\] Respectively center of spheres are \[(-3,4,1)\] and \[(5,-2,1).\] Midpoint of centres is \[(1,1,1).\] Satisfying this in the equation of plane, we get \[2a-3a+4a+6=0\Rightarrow a=-2.\]You need to login to perform this action.
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