A) \[8x+5y-11z+8=0\]
B) \[8x+5y-11z+8=0\]
C) \[8x-5y-11z+8=0\]
D) None of these
Correct Answer: C
Solution :
[c] Any plane through the line is \[(x+2y-z+1)+\lambda (3x-y-4z+3)=0.\] It passes through \[(1,1,1).\] \[\therefore \] \[(1+2-1+1)+\lambda (3-1-4+3)=0\Rightarrow \lambda =-3\] Therefore. The required plane is \[8x-5y-11z+8=0.\]You need to login to perform this action.
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