A) \[\frac{\sqrt{3}}{2}\]
B) \[\frac{\sqrt{2}}{3}\]
C) \[\frac{3}{7}\]
D) \[\frac{2}{7}\]
Correct Answer: D
Solution :
[d] \[\therefore \] DR?s of the normal of the plane \[=2,-3,6\] and Dr?s of x-axis is 1, 0, 0 And if \[\theta \]is the angle between the plane and x-axis, then \[\sin \theta \] \[=\frac{2(1)+(-3)(0)+(6)(0)}{\sqrt{{{2}^{2}}+{{(-3)}^{2}}+{{6}^{2}}}\sqrt{1}}=\frac{2}{7}\] \[\Rightarrow \theta ={{\sin }^{-1}}\left( \frac{2}{7} \right)\therefore a=\frac{2}{7}\]
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