A) 2
B) 3
C) 0
D) 1
Correct Answer: B
Solution :
The given equation is \[\tan x+\sec x=2\cos x;\] \[\Rightarrow \,\,\sin x+1=2{{\cos }^{2}}x\Rightarrow \sin x+1=2(1-{{\sin }^{2}}x);\] \[\Rightarrow \,\,\,2{{\sin }^{2}}x+\sin x-1=0;\] \[\Rightarrow \,\,\,(2\sin x-1)(sinx+1)=0\Rightarrow sin\,x=\frac{1}{2},-1.;\] \[\Rightarrow \,\,x=30{}^\circ ,150{}^\circ ,270{}^\circ .\]You need to login to perform this action.
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