A) forms an empty set
B) is only one
C) is only two
D) is more than 2
Correct Answer: B
Solution :
\[\sin \left( \frac{\pi x}{2\sqrt{3}} \right)={{x}^{2}}-2\sqrt{3}x+4={{(x-\sqrt{3})}^{2}}+1\] \[\because \] \[RHS\ge 1\]so, the solution exists If and only if \[x-\sqrt{3}=0\Rightarrow x=\sqrt{3}\] and then equation is obviously satisfied
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