A) -1
B) \[0\]
C) \[1\]
D) \[2\]
Correct Answer: C
Solution :
Given \[A=(\cos 12{}^\circ -\cos 36{}^\circ )(\sin 96{}^\circ +sin24{}^\circ )\] \[B=(\sin 60{}^\circ -\sin 12{}^\circ )(\cos 48{}^\circ -\cos 72{}^\circ )\] \[\frac{A}{B}=\frac{[-2\sin 24{}^\circ \sin 12{}^\circ ][2\sin 60{}^\circ \cos 36{}^\circ ]}{[2\cos 36{}^\circ \sin 24{}^\circ ][-2\sin 60{}^\circ \sin 12{}^\circ ]}\] \[\Rightarrow \,\,\frac{A}{B}=1\]You need to login to perform this action.
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