JEE Main & Advanced Mathematics Vector Algebra Question Bank Self Evaluation Test - Vector Algebra

  • question_answer
    Which one of the following is the unit vector perpendicular to both \[\vec{a}=-\hat{i}+\hat{j}+\hat{k}\] and\[\vec{b}=\hat{i}-\hat{j}+\hat{k}\]?

    A) \[\frac{\hat{i}+\hat{j}}{\sqrt{2}}\]

    B) \[\hat{k}\]

    C) \[\frac{\hat{j}+\hat{k}}{\sqrt{2}}\]

    D) \[\frac{\hat{i}-\hat{j}}{\sqrt{2}}\]

    Correct Answer: A

    Solution :

    [a] According to question \[a=-\hat{i}+\hat{j}+\hat{k}\] and \[b=\hat{i}-\hat{j}+\hat{k}\] Then, \[a\times b=\left| \begin{matrix}    i & j & k  \\    -1 & 1 & 1  \\    1 & -1 & 1  \\ \end{matrix} \right|\] \[=\hat{i}[1+1]-\hat{j}[-1-1]+\hat{k}[1-1]\] \[=2\hat{i}+2j+0=2(i+j)\] and \[|a\times b|=\sqrt{4+4}=2\sqrt{2}\] \[\therefore \] Required unit vector \[=\pm \frac{2(i+j)}{2\sqrt{2}}=\pm \frac{i+j}{\sqrt{2}}\]


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