A) \[\frac{1}{2}\]
B) 1
C) \[\frac{3}{2}\]
D) 2
Correct Answer: C
Solution :
[c] Let P. V of A, B and D be \[\vec{0},\,\vec{b}\] and \[\vec{d}\], respectively. Then P.V. of C, \[\vec{c}=\vec{b}+\vec{d}\]. Also P.V. of \[{{A}_{1}}=\vec{b}+\frac{{\vec{d}}}{2}\] and P.V. of \[{{B}_{1}}\] \[=\vec{d}+\frac{{\vec{b}}}{2}\Rightarrow \overrightarrow{A{{A}_{1}}}=\frac{3}{2}(\vec{b}+\vec{d})=\frac{3}{2}\overrightarrow{AC}\]You need to login to perform this action.
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