A) 9
B) 4
C) 5
D) 3
Correct Answer: C
Solution :
[c] Since, the moment about A is zero, hence \[\vec{F}\] passes through A. Taking A as origin. Let the line of action of force \[\vec{F}\] be y = mx. (see figure) moment about \[B=\frac{3m}{\sqrt{1+{{m}^{2}}}}|\vec{F}|=9....(1)\] Moment about \[C=\frac{4}{\sqrt{1+{{m}^{2}}}}|\vec{F}|=16...(2)\] Dividing (1) by (2), we get: \[m=\frac{3}{4}\Rightarrow |\vec{F}|=5N\].You need to login to perform this action.
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