JEE Main & Advanced Mathematics Vector Algebra Question Bank Self Evaluation Test - Vector Algebra

  • question_answer
    If \[{{a}^{2}}+{{b}^{2}}+{{c}^{2}}=1\] where \[a,\text{ }b,\text{ }c\text{ }\in \,\,R\text{ }\], then the maximum value of\[{{(4a-3b)}^{2}}+{{(5b-4c)}^{2}}+{{(3c-5a)}^{2}}\] is

    A) 25

    B) 50

    C) 144

    D) None of these

    Correct Answer: B

    Solution :

    [b] Let \[{{\vec{r}}_{1}}=a\hat{i}+b\hat{j}+c\hat{k},{{\vec{r}}_{2}}=3\hat{i}+4\hat{j}+5\hat{k}\] \[|{{\vec{r}}_{1}}\times {{\vec{r}}_{2}}{{|}^{2}}\le |{{\vec{r}}_{1}}{{|}^{2}}|{{\vec{r}}_{2}}{{|}^{2}}...(1)\] Now, \[{{\vec{r}}_{1}}\times {{\vec{r}}_{2}}=\left| \begin{matrix}    {\hat{i}} & {\hat{j}} & {\hat{k}}  \\    a & b & c  \\    3 & 4 & 5  \\ \end{matrix} \right|\] \[=\hat{i}(5b-4c)+\hat{j}(3c-5a)+\hat{k}(4a-3b)\] So, from (1): \[{{(5b-4c)}^{2}}+{{(3c-5a)}^{2}}+{{(4a-3b)}^{2}}\le 50\]


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