A) \[x=2,y=1\]
B) \[x=1,y=2\]
C) \[x=-2,y=1\]
D) \[x=-2,y=-1\]
Correct Answer: A
Solution :
[a] \[\overset{\to }{\mathop{u}}\,-\overset{\to }{\mathop{v}}\,=\overset{\to }{\mathop{w}}\,\] \[\left( 2x\overset{\to }{\mathop{\alpha }}\,+y\overset{\to }{\mathop{\beta }}\, \right)-\left( 2y\overset{\to }{\mathop{\alpha }}\,+3x\overset{\to }{\mathop{\beta }}\, \right)=2\overset{\to }{\mathop{\alpha }}\,-5\overset{\to }{\mathop{\beta }}\,\] \[(2x-2y)\overset{\to }{\mathop{\alpha }}\,+(y-3x)\overset{\to }{\mathop{\beta }}\,=2\overset{\to }{\mathop{\alpha }}\,-5\overset{\to }{\mathop{\beta }}\,\] \[\therefore 2x-2y=2...(i)\] and \[3x-y=-5...(ii)\] Solving equations (i) and (ii), we get \[x=2\] and \[y=1\]You need to login to perform this action.
You will be redirected in
3 sec