A) 1.25
B) 1.33
C) 1.4
D) 1.513
Correct Answer: C
Solution :
[c] \[n=\frac{(\mu -1)tD}{d}\] but \[\beta =\frac{\lambda D}{d}\Rightarrow \frac{D}{d}=\frac{\beta }{\lambda }\] \[n=(\mu -1)t\,\beta /\lambda \] \[20\beta =(\mu -1)2.5\times {{10}^{-3}}(\beta /5000\times {{10}^{-8}})\] \[\mu -1=\frac{20\times 5000\times {{10}^{-8}}}{2.5\times {{10}^{-3}}}\Rightarrow \mu =1.4\]
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