A) \[\lambda =\frac{{{d}^{2}}}{(2n+1)D}\]
B) \[\lambda =\frac{(2n+1){{d}^{2}}}{D}\]
C) \[\lambda =\frac{{{d}^{2}}}{(n+1)D}\]
D) \[\lambda =\frac{(n+1)D}{{{d}^{2}}}\]
Correct Answer: A
Solution :
[a] \[{{n}^{th}}\] minimum has a distance from the centre \[=x=(2n+1)\frac{1}{2}\frac{\lambda D}{d}\] For a point on the screen directly in front of one of the slits, \[x=d/2\] \[\therefore \] for minimum intensity in front of one of the slits \[\frac{d}{2}=(2n+1)\frac{\lambda }{2}\frac{D}{d}\] \[\therefore \,\,\,\lambda =\frac{{{d}^{2}}}{(2n+1)D}\]
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