A) \[\frac{16}{9}\]
B) \[\frac{7}{1}\]
C) \[\frac{7}{1}\]
D) \[\frac{49}{1}\]
Correct Answer: D
Solution :
[d] \[Intensity\propto ~\left( amplitude \right)\] \[\frac{{{I}_{1}}}{{{I}_{2}}}=\frac{16}{9}=\frac{a_{1}^{2}}{a_{2}^{2}}\Rightarrow {{a}_{1}}=4\]; \[{{a}_{2}}=3\] Therefore the ratio of intensities of bright and dark parts \[\frac{{{I}_{Bright}}}{{{I}_{Dark}}}=\frac{{{({{a}_{1}}+{{a}_{2}})}^{2}}}{{{({{a}_{1}}-{{a}_{2}})}^{2}}}=\frac{{{(4+3)}^{2}}}{{{(4-3)}^{2}}}=\frac{49}{1}\]
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