A) \[\cot \frac{\alpha -\beta }{2}\cot \frac{\alpha +\beta }{2}\]
B) \[\tan \frac{\alpha +\beta }{2}\cot \frac{\alpha -\beta }{2}\]
C) \[\sin \frac{\alpha +\beta }{2}\cos \frac{\alpha -\beta }{2}\]
D) \[\tan \frac{\alpha -\beta }{2}\cot \frac{\alpha +\beta }{2}\]
Correct Answer: D
Solution :
[d] \[\frac{\Delta {{P}_{1}}}{\Delta {{P}_{2}}}=\frac{\sin \alpha -\sin \beta }{\sin \alpha +sin\beta }=\tan \frac{\alpha -\beta }{2}\cot \frac{\alpha +\beta }{2}\]You need to login to perform this action.
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