A) \[\frac{D\lambda }{d}\]
B) \[\frac{2D\lambda }{d}\]
C) \[\frac{3D\lambda }{d}\]
D) \[\frac{4D\lambda }{d}\]
Correct Answer: D
Solution :
[d] Due to reflection virtual source will be formed at distance D from mirror. The effective distance of the screen\[=2D+2D=4D\] \[\therefore \] Fringe width\[=\frac{4D\lambda }{d}\]You need to login to perform this action.
You will be redirected in
3 sec