JEE Main & Advanced Physics Wave Optics / तरंग प्रकाशिकी Question Bank Self Evaluation Test - Wave Optics

  • question_answer
    A plastic sheet (refractive index =1.6) covers one slit of a double slit arrangement meant for the Young's experiment. When the double slit is illuminated by monochromatic light (wavelength in air\[=6600\,\overset{o}{\mathop{A}}\,\]), the centre of the screen appears dark rather than bright. The minimum thickness of the plastic sheet to be used for this to happen is:

    A) \[3300\overset{o}{\mathop{A}}\,\]

    B) \[6600\overset{o}{\mathop{A}}\,\]

    C) \[2062\overset{o}{\mathop{A}}\,\]

    D) \[5500\overset{o}{\mathop{A}}\,\]

    Correct Answer: D

    Solution :

    [d] The path difference produced by a sheet \[\Delta =(\mu -1)t\] According to the given condition (for minimum thickness) \[(\mu -1)t=\frac{\lambda }{2}\] \[\therefore \,\,\,t=\frac{\lambda }{2(\mu -1)}=\frac{6600\times {{10}^{-10}}}{2(1.6-1)}=5500\overset{o}{\mathop{A}}\,\]


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