A) \[({{l}_{1}}-{{l}_{3}})+({{l}_{2}}-{{l}_{4}})=n\lambda \]
B) \[({{l}_{1}}-{{l}_{2}})+({{l}_{3}}-{{l}_{4}})=\frac{(2n-1)}{2}\lambda \]
C) \[({{l}_{1}}-{{l}_{3}})+({{l}_{2}}-{{l}_{4}})=\frac{(2n-1)\lambda }{2}\]
D) \[({{l}_{1}}-{{l}_{2}})+({{l}_{4}}-{{l}_{3}})=\frac{(2n-1)\lambda }{2}\]
Correct Answer: B
Solution :
[b] For dark fringe, Path difference \[=(2n-1)\frac{\lambda }{2}\]
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