A) dependent on intensity of refracted light
B) same
C) smaller
D) larger
Correct Answer: C
Solution :
[c] From \[\mu =\frac{c}{v}-\frac{n{{\lambda }_{v}}}{n{{\lambda }_{m}}}\], \[{{\lambda }_{m}}=\frac{{{\lambda }_{v}}}{\mu }\] Here, c = velocity of light in vacuum and v= velocity of light in medium m= refractive index of the medium. Hence, wavelength in medium \[({{\lambda }_{m}})<{{\lambda }_{v}}(\because \,\mu >1,\,\,given)\] So, the required wavelength decreases.
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