JEE Main & Advanced Physics Wave Optics / तरंग प्रकाशिकी Question Bank Self Evaluation Test - Wave Optics

  • question_answer
    A wedged shaped air film having an angle of 40 second is illuminated by a monochromatic light and the fringes are observed vertically down through a microscope. The fringe separation between two consecutive bright fringes is 0.12 cm. The wavelength of light is:

    A) \[~5545\overset{o}{\mathop{A}}\,\]

    B) \[6025\overset{o}{\mathop{A}}\,\]

    C) \[4925\overset{o}{\mathop{A}}\,\]

    D) \[~4655\overset{o}{\mathop{A}}\,\]

    Correct Answer: D

    Solution :

    [d]  \[\beta =\frac{\lambda }{2\mu \tan \alpha }\simeq \frac{\lambda }{2\mu \alpha }\] \[\therefore \,\,\lambda =\beta \times 2\mu \alpha \] \[=0.12\times {{10}^{-2}}\times 2\times 1\times \left( \frac{40}{60\times 60}\times \frac{\pi }{180} \right)\] \[=4655\overset{o}{\mathop{A}}\,\].


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