JEE Main & Advanced Physics Wave Optics / तरंग प्रकाशिकी Question Bank Self Evaluation Test - Wave Optics

  • question_answer
    In YDSE distance between the \[{{S}_{1}}\]and\[{{S}_{2}}\]is d. \[{{P}_{1}}\]and\[{{P}_{2}}\]are two points equidistance from O at an angular position \[\beta \]as shown. A parallel beam of monochromatic light is incident at an angle a on the slits. Then the ratio of path difference at\[{{P}_{1}}\]and\[{{P}_{2}}\]is:

    A) \[\cot \frac{\alpha -\beta }{2}\cot \frac{\alpha +\beta }{2}\]         

    B) \[\tan \frac{\alpha +\beta }{2}\cot \frac{\alpha -\beta }{2}\]

    C) \[\sin \frac{\alpha +\beta }{2}\cos \frac{\alpha -\beta }{2}\]          

    D) \[\tan \frac{\alpha -\beta }{2}\cot \frac{\alpha +\beta }{2}\]

    Correct Answer: D

    Solution :

    [d] \[\frac{\Delta {{P}_{1}}}{\Delta {{P}_{2}}}=\frac{\sin \alpha -\sin \beta }{\sin \alpha +sin\beta }=\tan \frac{\alpha -\beta }{2}\cot \frac{\alpha +\beta }{2}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner