A) \[525\times {{10}^{-9}}m\]
B) \[344\times {{10}^{-3}}m\]
C) \[3.44\times {{10}^{-5}}m\]
D) None of the above
Correct Answer: C
Solution :
[c] The reflections from the boundaries will cause a net \[180{}^\circ \] phase shift. The condition for bright fringes is \[2t=(m+{\scriptstyle{}^{1}/{}_{2}}){{\lambda }_{film}}\] Now, m=124 since there is a bright fringe for m = 0 and \[{{\lambda }_{film}}=\frac{\lambda }{n}\] \[t=\frac{\left( m+\frac{1}{2} \right){{\lambda }_{film}}}{2}=\frac{\left( m+\frac{1}{2} \right)\lambda }{2n}\] \[=\frac{\left( 124+\frac{1}{2} \right)(552\times {{10}^{-9}}m)}{2\times (1.00)}=3.44\times {{10}^{-5}}m\]
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