JEE Main & Advanced Physics Wave Optics / तरंग प्रकाशिकी Question Bank Self Evaluation Test - Wave Optics

  • question_answer
    In the figure shown in a YDSE, a parallel beam of light is incident on the slits from a medium of refractive index \[{{n}_{1}}\].The wavelength of light in this medium is\[{{\lambda }_{1}}\]. A transparent slab of thickness t and refractive index is put in front of one slit. The medium between the screen and the plane of the slits is \[{{n}_{2}}\]. The phase difference between the light waves reaching point O (symmetrical, relative to the slit) is

    A) \[\frac{2\pi }{{{n}_{1}}{{\lambda }_{1}}}({{n}_{3}}-{{n}_{2}})t\]      

    B) \[\frac{2\pi }{{{\lambda }_{1}}}({{n}_{3}}-{{n}_{2}})t\]

    C) \[\frac{2\pi {{n}_{1}}}{{{n}_{2}}{{\lambda }_{1}}}\left( \frac{{{n}_{3}}}{{{n}_{2}}}-1 \right)t\]

    D)        \[\frac{2\pi {{n}_{1}}}{{{\lambda }_{1}}}({{n}_{3}}-{{n}_{2}})t\]

    Correct Answer: A

    Solution :

    [a] Optical path difference between the waves \[=({{n}_{3}}-{{n}_{2}})t\] \[\therefore \] Phase difference \[=2\pi \frac{({{n}_{3}}-{{n}_{2}})t}{{{\lambda }_{(Vacuum)}}}=2\pi \frac{({{n}_{3}}-{{n}_{2}})t}{{{n}_{1}}{{\lambda }_{1}}}\]


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