JEE Main & Advanced Physics Wave Optics / तरंग प्रकाशिकी Question Bank Self Evaluation Test - Wave Optics

  • question_answer
    A double slit, \[{{S}_{1}}-{{S}_{2}}\]is illuminated by a light source S emitting light of wavelength\[\lambda \]. The slits are separated by a distance d. A plane mirror is placed at a distance D in front of the slits and a screen is placed at a distance 2D behind the slits. The screen receives light reflected only by the plane mirror. The fringe-width of the interference pattern on the screen is       

    A) \[\frac{D\lambda }{d}\]

    B) \[\frac{2D\lambda }{d}\]

    C) \[\frac{3D\lambda }{d}\]

    D) \[\frac{4D\lambda }{d}\]

    Correct Answer: D

    Solution :

    [d] Due to reflection virtual source will be formed at distance D from mirror. The effective distance of the screen\[=2D+2D=4D\] \[\therefore \] Fringe width\[=\frac{4D\lambda }{d}\]


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