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JEE Main & Advanced Physics Wave Optics / तरंग प्रकाशिकी Question Bank Self Evaluation Test - Wave Optics

  • question_answer
    In figure, Young's double slit experiment Q is the position of the first bright fringe on the right side of O. P is the\[{{11}^{th}}\]fringe on the other side, as measured from Q. If\[\lambda =6000\overset{o}{\mathop{A}}\,\], then \[{{S}_{1}}B\]will be equal to                             

    A) \[6\times {{10}^{-6}}m\]

    B) \[6.6\times {{10}^{-6}}m\]

    C) \[3.318\times {{10}^{-7}}m\]

    D) \[3.144\times {{10}^{-7}}m\]

    Correct Answer: A

    Solution :

    [a]  Path difference between first and \[{{11}^{th}}\] bright fringe \[{{S}_{1}}B\] (10 bright fringes) \[=10\lambda \] \[=10\times (6000\times {{10}^{-7}})m=6\times {{10}^{-6}}m\]


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