A) \[\frac{{{\lambda }_{1}}{{\lambda }_{2}}}{2\,Dd}\]
B) \[({{\lambda }_{1}}-{{\lambda }_{2}}).\frac{2d}{D}\]
C) LCM of \[{{\lambda }_{1}}.\frac{D}{d}\] and \[{{\lambda }_{2}}.\frac{D}{d}\]
D) HCF of \[\frac{{{\lambda }_{1}}D}{d}\] and \[\frac{{{\lambda }_{2}}D}{d}\]
Correct Answer: C
Solution :
[c] \[{{y}_{n}}=\frac{nD{{\lambda }_{1}}}{d}=\frac{(n+1)D{{\lambda }_{2}}}{d}\] or \[n=\left( \frac{{{\lambda }_{2}}}{{{\lambda }_{2}}-{{\lambda }_{1}}} \right)\] and \[{{y}_{n}}=\left( \frac{{{\lambda }_{1}}{{\lambda }_{2}}}{{{\lambda }_{2}}-{{\lambda }_{1}}} \right)\left( \frac{D}{d} \right)\].
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