A) inversely as the wavelength
B) directly as the width of the slit
C) directly as the distance between the slit and the screen
D) inversely as the size of the source from which the slit is illuminated
Correct Answer: C
Solution :
[c] The width of the diffraction band is given by \[\beta =\frac{\lambda D}{d}\,\,\,\,\,\,\,\,\,\,\,\Rightarrow \,\,\,\,\,\,\,\,\,\beta \propto \lambda \] \[\beta \,\,\,\,\,\,\,\propto \,\,\,\,\,\,\,\,D\] and \[\beta \,\,\,\,\,\,\,\propto \,\,\,\,\,\frac{1}{d}\].
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